2y^2+y+72=

Solution for 2y^2+y+72= equation:

Simplifying
2y2 + y + 72 = 0

Reorder the terms:
72 + y + 2y2 = 0

Solving
72 + y + 2y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
36 + 0.5y + y2 = 0

Move the constant term to the right:

Add '-36' to each side of the equation.
36 + 0.5y + -36 + y2 = 0 + -36

Reorder the terms:
36 + -36 + 0.5y + y2 = 0 + -36

Combine like terms: 36 + -36 = 0
0 + 0.5y + y2 = 0 + -36
0.5y + y2 = 0 + -36

Combine like terms: 0 + -36 = -36
0.5y + y2 = -36

The y term is y.  Take half its coefficient (0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
0.5y + 0.25 + y2 = -36 + 0.25

Reorder the terms:
0.25 + 0.5y + y2 = -36 + 0.25

Combine like terms: -36 + 0.25 = -35.75
0.25 + 0.5y + y2 = -35.75

Factor a perfect square on the left side:
(y + 0.5)(y + 0.5) = -35.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.